- 时间规划-GESP202306一级题一
 dn
- @ 2024-3-23 20:18:55
 
#include<bits/stdc++.h>
using namespace std;
int main()
{
	int a,b,c,d;
	cin>>a>>b>>c>>d;
	int e=(c-a)*60;
	e+=d-b;
	cout<<e;
	return 0;
}
        0 comments
  
  No comments so far...
            Information
- ID
 - 725
 - Time
 - 1000ms
 - Memory
 - 256MiB
 - Difficulty
 - 6
 - Tags
 - # Submissions
 - 120
 - Accepted
 - 45
 - Uploaded By